[tex]\it \mathcal{A} = 56\cdot25=1400m^2\\ \\ 100\%-60\%=40\%\ din\ \mathcal{A}\ (suprafa\c{\it t}a\ pavat\breve a)\\ \\ \dfrac{40}{100}\cdot1400=40\cdot14=560\ m^2\ (suprafa\c{\it t}a\ pavat\breve a)\\ \\ 560\cdot0,25=140\ t\ de\ piatr\breve a\ s-au\ folosit[/tex]
