Răspuns:
MNa=23g/mol
MNaCl=23+35,5=58,5
2x23g.......................2x58,5g
2Na + Cl2 → 2NaCl reactie de combinare
10g................................xg
x=10x2x58,5/2x23=calculeaza
n=m/M=10/23=0,43moli
1mol Na..............................6,023x10²³atomi
2x0,43moliNa......................y atomi
y=2x0,43x.6,023x10²³atomi/1=calculeaza.
Explicație: