Răspuns:
[tex]a)mg = \sqrt{6 \times 8} = \sqrt{48} = \sqrt{16 \times 3} = 4 \sqrt{3} \\ b)mg = \sqrt{10 \times 15} = \sqrt{150} = \sqrt{25 \times 6} = 5 \sqrt{6} \\ c)mg = \sqrt{ \sqrt{3} \times \sqrt{27} } = \sqrt{ \sqrt{81} } = \sqrt{9} = 3 \\ d)mg = \sqrt{2 \sqrt{45} \times 3 \sqrt{20} } = \sqrt{6 \sqrt{900} } = \sqrt{6 \times 30} = \sqrt{180} = \sqrt{4 \times 45} = 2 \sqrt{45} = 2 \sqrt{9 \times 5 } = 2 \times 3 \sqrt{5} = 6 \sqrt{5} \\ e) \sqrt{7 \sqrt{5} \times \sqrt{125} } = \sqrt{7 \times \sqrt{625} } = \sqrt{7 \times 25} = \sqrt{7} \times \sqrt{25} = 5 \sqrt{7} [/tex]
[tex]8)a) {x}^{2} = 25 \\ x1 = \sqrt{25} = 5 \\ x2 = - \sqrt{25} = - 5 \\ b) {x}^{2} = - 16 \\ x = \sqrt{ - 16} \: nu \: apartine \: multimii \: numerelor \: reale \\ c)3 {x}^{2} = 0 \\ {x}^{2} = 0 \\ x = 0 \\ d) {x}^{2} + 5 = 15 \\ {x}^{2} = 10 \\ x1 = \sqrt{10} \\ x2 = - \sqrt{10} \\ e) {x}^{2} \div 3 = 15 \\ {x}^{2} = 5 \\ x1 = \sqrt{5} \\ x2 = - \sqrt{5} [/tex]
