Explicație pas cu pas:
a)
[tex]a = 3 \cdot {3}^{29} - 8 \cdot {9}^{14} = 3 \cdot {3}^{29} - 8 \cdot {( {3}^{2} )}^{14} = 3 \cdot {3}^{29} - 8 \cdot {3}^{28} = {3}^{28} \cdot (3 \cdot 3 - 8) = {3}^{28} \cdot (9 - 8) = {3}^{28} \cdot 1 = \bf {3}^{28}[/tex]
b)
[tex]b = {( {8}^{4} )}^{3} : {16}^{8} = {8}^{4 \cdot 3} : {( {2}^{4} )}^{8} = {( {2}^{3} )}^{12} : {2}^{4 \cdot 8} = {2}^{36} : {2}^{32} = {2}^{36 - 32} = \bf {2}^{4}[/tex]
c)
[tex]{3}^{28} = {3}^{3} \cdot {3}^{25} = 27 \cdot {3}^{25}[/tex]
[tex]{2}^{4} = 16[/tex]
[tex]{3}^{28} > {2}^{4} \implies a > b[/tex]
