Explicație pas cu pas:
a)
1.
[tex]3x + 3 = 0 \iff 3x = - 3 \\ x = - \frac{3}{3} \implies x = - 1[/tex]
2.
[tex]- 5x - 5 = 0 \iff - 5x = 5 \\ x = - \frac{5}{5} \implies x = - 1[/tex]
b)
1.
[tex]\sqrt{3}x + \sqrt{2} = 0 \iff \sqrt{3} x = - \sqrt{2} \\ x = - \frac{^{ \sqrt{3} )} \sqrt{2} }{ \sqrt{3} } \implies x = - \frac{ \sqrt{6} }{3} [/tex]
2.
[tex]- \sqrt{6}x + \sqrt{3} = 0 \iff - \sqrt{6} x = - \sqrt{3} \\ x = \frac{^{ \sqrt{6} )} \sqrt{3} }{ \sqrt{6} } \iff x = \frac{ \sqrt{18} }{6} \\ \implies x = \frac{ 3\sqrt{2} }{2} [/tex]
