va rooooooooooog dau și corona

[tex]\it a)\ \ (30,\ 20) = 10\\ \\ 5^{30}=(5^3)^{10}=125^{10}\\ \\ 7^{20}=(7^2)^{10}=49^{10}[/tex]
[tex]\it b)\ \ (24,\ 36)=12\\ \\ \\\Big(\dfrac{1}{5}\Big)^{24}=\Big[\Big(\dfrac{1}{5}\Big)^{2}\Big]^{12}=\Big(\dfrac{1}{25}\Big)^{12}\\ \\ \\ \Big(\dfrac{2}{3}\Big)^{36}=\Big[\Big(\dfrac{2}{3}\Big)^{3}\Big]^{12}=\Big(\dfrac{8}{27}\Big)^{12}[/tex]