Explicație pas cu pas:
se aduce la același numitor, prin amplificarea fracțiilor:
m)
[tex]7 - \frac{5}{6} = \frac{7 \times 6 - 5}{6} = \frac{42 - 5}{6} = \frac{37}{6} \\ [/tex]
n)
[tex]\frac{3}{8} - \frac{7}{56} = \frac{3}{8} - \frac{1}{8} = \frac{3 - 1}{8} = \frac{2}{4} = \frac{1}{4} \\ [/tex]
o)
[tex]\frac{4}{5} + \frac{3}{2} + \frac{7}{20} = \frac{4 \times 4}{20} + \frac{3 \times 10}{20} + \frac{7}{20} = \frac{16 + 30 + 7}{20} = \frac{53}{20} \\ [/tex]
p)
[tex]\frac{3}{4} + \frac{5}{8} - \frac{2}{4} = \frac{3 \times 2}{8} + \frac{5}{8} - \frac{2 \times 2}{8} = \frac{6 + 5 - 4}{8} = \frac{7}{8} \\ [/tex]
r)
[tex]\frac{7}{4} + \frac{1}{12} - \frac{1}{3} = \frac{7 \times 3}{12} + \frac{1}{12} - \frac{1 \times 4}{12} = \frac{21 + 1 - 4}{12} = \frac{18}{12} = \frac{3}{2} \\ [/tex]
s)
[tex]\frac{2}{3} - \frac{4}{9} + \frac{7}{3} = \frac{2 \times 3}{3} - \frac{4}{9} + \frac{7 \times 3}{9} = \frac{6 - 4 + 21}{9} = \frac{23}{9} \\ [/tex]
ș)
[tex]5 - \frac{3}{10} = \frac{5 \times 10 - 3}{10} = \frac{50 - 3}{10} = \frac{47}{10} \\ [/tex]
t)
[tex]\frac{13}{16} - \frac{5}{32} = \frac{13 \times 2}{32} - \frac{5}{32} = \frac{26 - 5}{32} = \frac{21}{32} \\ [/tex]
