sin C =1/2 => <C=30° => (Din Teorema <30°) AB=BC/2=25/2=12,5 cm
Din Teorema lui Pitagora in triunghiul ABC =>
[tex] {ac}^{2} = {bc}^{2} - {ab}^{2} = {25}^{2} - ( { \frac{25}{2} })^{2} = 625 - \frac{625}{4} = \frac{2500 - 625}{4} = \frac{1875}{4} = > ac = \sqrt{ \frac{1875}{4} } = \frac{25 \sqrt{3} }{2} = 12.5 \sqrt{3} [/tex]
