Explicație pas cu pas:
a)
[tex]\left( - \frac{1}{4} \right) \div \left(\frac{50}{9} \div \frac{25}{3} \right) = - \frac{1}{4} \div \left(\frac{50}{9} \cdot \frac{3}{25} \right) = - \frac{1}{4} \div \frac{2}{3} = - \frac{1}{4} \cdot \frac{3}{2} = - \frac{3}{8} \\ [/tex]
b)
[tex]\left( - \frac{5}{13} \right) + \left( - \frac{3}{26} \right) \div \frac{7}{2} = - \frac{5}{13} - \frac{3}{26}\cdot \frac{2}{7} = - \frac{5}{13} - \frac{3}{91} = - \frac{35 + 3}{91} = - \frac{38}{91} \\ [/tex]
c)
[tex]\left( - \frac{3}{5} - \frac{2}{15} \div \frac{4}{3} \right) \div \frac{7}{5} = \left( - \frac{3}{5} - \frac{2}{15} \cdot \frac{3}{4} \right) \cdot \frac{5}{7} = \left( - \frac{3}{5} - \frac{1}{10} \right) \cdot \frac{5}{7} = \left( - \frac{6 + 1}{10} \right) \cdot \frac{5}{7} = \left( - \frac{7}{10} \right) \cdot \frac{5}{7} = - \frac{1}{2} \\ [/tex]
d)
[tex]\left(\frac{6}{7} + \frac{9}{14} \div \frac{27}{2} \right) \div \frac{19}{7} = \left(\frac{6}{7} + \frac{9}{14} \cdot \frac{2}{27} \right) \cdot \frac{7}{19} = \left(\frac{6}{7} + \frac{1}{21} \right) \cdot \frac{7}{19} = \frac{18 + 1}{21} \cdot \frac{7}{19} = \frac{19}{21} \cdot \frac{7}{19} = \frac{1}{3} \\ [/tex]
a)
[tex]\frac{4}{25} \div \frac{16}{5} - \frac{11}{10} \div \frac{33}{2} = \frac{4}{25} \cdot \frac{5}{16} - \frac{11}{10} \cdot \frac{2}{33} = \frac{1}{20} - \frac{1}{15} = \frac{3 - 4}{60} = - \frac{1}{60} \\ [/tex]
b)
[tex]1\frac{6}{11} \div \frac{3}{44} - \frac{5}{27} \div \frac{10}{9} = \frac{17}{11} \cdot \frac{44}{3} - \frac{5}{27} \cdot \frac{9}{10} = \frac{17}{1} \cdot \frac{4}{3} - \frac{1}{3} \cdot \frac{1}{2} = \frac{136 - 1}{6} = \frac{135}{6} = \frac{45}{2} \\ [/tex]
