Explicație pas cu pas:
∢ACM ≡ ∢MCB => CM este bisectoare
[tex]\frac{AC}{BC} = \frac{AM}{BM} \iff \frac{AC + BC}{BC} = \frac{AM + BM}{BM} \\ \frac{18 + 15}{15} = \frac{AB}{BM} \iff \frac{33}{15} = \frac{12}{BM} \\ BM = \frac{15 \times 12}{33} \implies BM = 5.(45) \: cm[/tex]
