Răspuns:
∆ABC dreptunghicAD_l_BC
Explicație pas cu pas:
1.AB=2cm AD=2√3cm
∆ABD BD=√4-4×3
AB ipotenuză >AD sau BD 4√3>4 fals
2.AB=6cm AC=8cm
BC=√AB²+AC²=√36+64=√100=10cm
Perimetrul=10+8+6=24cm
Aria=AB×AC/2=6×8/2=24cm²
3.AC=4√3cm catetă BC=8cm ip
AB=√BC²-AC²=64-16×3=16cm
P=16+8+4√3=24+4√3
A=AC×AB/2=4√3×16/2=32√3cm²
4.DB=9cm DC=16cm
h=AD=√DB×DC=√9×16=12cm
AB=√DB²+AD²=√81+144=√225=15cm
BC=DB+DC=9+16=25cm
AC=√25²-15²=√400=20cm
P=AB+AC+BC=20+25+15=60cm
A=AB×AC/2=15×20/2=150cm²
