Fie suma Anei a, suma lui Bogdan b, iar suma Corinei c. Stim ca:
[tex]a+\frac{b}{2}=115, \ b+\frac{c}{4}=245, \ c+\frac{a}{3}=310[/tex]
Folosind primele doua ecuatii obtinem ca
[tex]245-230=b+\frac{c}{4}-2(a+\frac{b}{2})=\frac{c}{4}-2a\implies 15=\frac{c}{4}-2a[/tex]
Substituind in cea de-a treia relatie, obtinem ca
[tex]310=c+\frac{a}{3}=(60+8a)+\frac{a}{3}\implies 930=180+25a\implies a=30[/tex]
Uitandu-ne in celelalte relatii, putem deduce ca [tex]b=170, \ c=300[/tex]
