Explicație pas cu pas :
[tex]a = ( \: {27}^{2} )^{6} \div {81}^{8} - {2}^{16} \times {4}^{3} \div {8}^{6} \\ [/tex]
[tex]a = {27}^{12} \div {81}^{8} - {2}^{16} \times {4}^{3} \div {8}^{6} \\ [/tex]
[tex]a = ( {3}^{3} )^{12} \div ( {3}^{4} )^{8} - {2}^{16} \times ({2}^{2} )^{3} \div ( {2}^{3} ) ^{6} \\ [/tex]
[tex]a = {3}^{36} \div {3}^{32} - {2}^{16} \times {2}^{6} \div {2}^{18} \\ [/tex]
[tex]a = {3}^{36 - 2} - {2}^{16 + 6} \div {2}^{18} \\ [/tex]
[tex]a = {3}^{4} - {2}^{22} \div {2}^{18} [/tex]
[tex]a = {3}^{4} - {2}^{22 - 18} [/tex]
[tex]a = {3}^{4} - {2}^{4} [/tex]
[tex]a = 81 - 16[/tex]
[tex]\boxed{a = 65}[/tex]
⇒ Andrei este cel care a determinat corect răspunsul : a)
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Formule de calcul cu puteri :
[tex]\bf{ {a}^{m} \div {a}^{n} = {a}^{m - n} }[/tex]
[tex]\bf{ {a}^{m} \times {a}^{n} = {a}^{m + n} }[/tex]
[tex]\bf{ ({a}^{m})^{n} = {a}^{m \times n} }[/tex]
[tex]\bf{(a \times b) ^{m} = {a}^{m} \times {b}^{m} }[/tex]
[tex]\bf{(a \div b) ^{m} = {a}^{m} \div {b}^{m} }[/tex]
