[tex]x=\left(\frac{2}{\sqrt{12}}+\frac{9}{\sqrt{27}}+\frac{6}{\sqrt{108}}\right)\left(\frac{1}{\sqrt{3}}\right)^{-1}[/tex]
[tex]x=\left(\frac{1}{\sqrt{3}}\right)^{-1}\left(\frac{1}{\sqrt{3}}+\frac{9}{\sqrt{27}}+\frac{6}{\sqrt{108}}\right)[/tex]
[tex]x=\left(\frac{1}{\sqrt{3}}\right)^{-1}\left(\frac{1}{\sqrt{3}}+\frac{3}{\sqrt{3}}+\frac{6}{\sqrt{108}}\right)[/tex]
[tex]=\left(\frac{1}{\sqrt{3}}\right)^{-1}\left(\frac{1}{\sqrt{3}}+\frac{1}{\sqrt{3}}+\frac{3}{\sqrt{3}}\right)[/tex]
[tex]x=\sqrt{3}\left(\frac{1}{\sqrt{3}}+\frac{1}{\sqrt{3}}+\frac{3}{\sqrt{3}}\right)[/tex]
[tex]x=\sqrt{3}\left(\frac{5\sqrt{3}}{3}\right)[/tex]
[tex]x=\frac{5\sqrt{3}}{3}\sqrt{3}[/tex]
[tex]x=\frac{5\sqrt{3}\sqrt{3}}{3}[/tex]
[tex]x=\frac{15}{3}[/tex]
[tex]x =5[/tex]
[tex]y=\left(5^6\right)^3\cdot 25^3:125^8[/tex]
[tex]y=\frac{\left(5^6\right)^3\cdot \:25^3}{125^8}[/tex]
[tex]y =\frac{5^{18}\cdot \:5^6}{5^{24}}[/tex]
[tex]y =\frac{5^{24}}{5^{24}}[/tex]
[tex]y=1[/tex]
Sper ca te-am ajutat!
