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9.Calculați
a.[-0,(3)]‐²
b.3‐²​


9Calculați A03b3 class=

Răspuns :

Răspuns:

[-(0,(3)]⁻2=(-3/9)⁻²=(-1/3)⁻²=(-3)²=9
b)3⁻²=1/3²=1/9

Explicație pas cu pas:

[tex]\it a)\ \ [-0,(3)] ^{-2}=\Big(-\dfrac{3}{9}\Big)^{-2}=\Big(\dfrac{3}{9}\Big)^{-2}=\Big(-\dfrac{3}{9}\Big)^{-2}=\Big(\dfrac{9}{3}\Big)^{2}=3^2=9\\ \\ \\ b)\ \ 3^{-2}=\dfrac{1}{3^2}=\dfrac{1}{9}[/tex]