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11 13
5 5
d) (9
+
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An +5


11 13 5 5 D 9 An 5 class=

Răspuns :

Răspuns:

Explicație pas cu pas:

[tex]( \frac{1}{9} + \frac{1}{5} \div \frac{3}{5} ) {}^{3} \div ( \frac{4}{9} ) {}^{3} = ( \frac{1}{9} + \frac{1}{\not{5}} \times \frac{\not{5}}{3} ){}^{3} \div ( \frac{4}{9} ) {}^{3} = ( \frac{1}{9} + \frac{ {}^{3)} 1}{3} ) {}^{3} \div ( \frac{4}{9} ) {}^{3} \\ [/tex]

[tex] = ( \frac{1}{9} + \frac{3}{9} ) {}^{3} \div ( \frac{4}{9} ) {}^{3} = ( \frac{4}{9} ) {}^{3} \div ( \frac{4}{9} ) {}^{3} = \boxed{1} \\ [/tex]