11 13
5 5
d) (9
+
()
An +5

Răspuns:
Explicație pas cu pas:
[tex]( \frac{1}{9} + \frac{1}{5} \div \frac{3}{5} ) {}^{3} \div ( \frac{4}{9} ) {}^{3} = ( \frac{1}{9} + \frac{1}{\not{5}} \times \frac{\not{5}}{3} ){}^{3} \div ( \frac{4}{9} ) {}^{3} = ( \frac{1}{9} + \frac{ {}^{3)} 1}{3} ) {}^{3} \div ( \frac{4}{9} ) {}^{3} \\ [/tex]
[tex] = ( \frac{1}{9} + \frac{3}{9} ) {}^{3} \div ( \frac{4}{9} ) {}^{3} = ( \frac{4}{9} ) {}^{3} \div ( \frac{4}{9} ) {}^{3} = \boxed{1} \\ [/tex]