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b) 2sin 60- 4cos 30 +3tg 60= ?
am nevoie urgent, day coroana ​


Răspuns :

Explicație pas cu pas:

[tex]2sin 60- 4cos 30 +3tg 60 = 2 \times \frac{ \sqrt{3} }{2} - 4 \times \frac{ \sqrt{3} }{2} +3 \times \sqrt{3} = \sqrt{3} - 2 \sqrt{3} + 3 \sqrt{3} = 4 \sqrt{3} - 2 \sqrt{3} = 2 \sqrt{3}[/tex]