Punctul 2 ,am nevoie urgent sunt la teza.

[tex]cos = \frac{cateta alaturata}{ipotenuza}[/tex]
[tex]cos B = \frac{AB}{BC}[/tex]
[tex]\frac{3}{5} = \frac{AB}{10}[/tex]
[tex]AB = \frac{30}{5} \\AB=6[/tex]
[tex]BC=10\\T. Pitagora[/tex]=> [tex]AB^{2} +AC^{2} =BC^{2}[/tex]
[tex]6^{2}+AC^{2}=10^{2}[/tex]
[tex]36+AC^{2} =100[/tex]
[tex]AC^{2} =100-36=64\\AC=\sqrt{64} \\AC=8[/tex]
[tex]aria =\frac{cateta1*cateta2}{2} \\aria=\frac{AB*AC }{2} \\aria= \frac{6*8}{2} \\aria = \frac{48}{2} \\aria = 24[/tex]