Va rog!!! Pana la ora 11:00!!!
CE este paralel cu AD!!!

CE=AD=12
DC=AE=12
EB=32-AE
EB=32-12=20
BC=16
Fie CM⊥EB
[tex]CM=\frac{CE\times BC}{EB} =\frac{12\times 16}{20} =9,6[/tex]
[tex]A_{ABCD}=\frac{44\times 9,6}{2} =211,2cm^2[/tex]
DE=BC=16
DE⊥CE (CE secanta, ∡DEC=∡BCE)
[tex]A_{AECD}=DE\times EC=16\times12=192[/tex]
[tex]A_{DEBC}=CE\times DE=12\times 16=192cm^2[/tex]