Aflam AC din Pitagora
AC²=AB²+BC²
AC²=16+64=80
AC=4√5 cm
[tex]sinC=\frac{AB}{AC} =\frac{4}{4\sqrt{5} } =\frac{\sqrt{5} }{5}[/tex]
[tex]cosC=\frac{BC}{AC} =\frac{8}{4\sqrt{5} } =\frac{2\sqrt{5} }{5}[/tex]
[tex]tgC=\frac{AB}{BC} =\frac{4}{8} =\frac{1}{2}[/tex]
[tex]ctgC=\frac{BC}{AB} =2[/tex]
