👤

n/9 = a rest 7, n/8 = b rest 5. cat este restul lui 72:n ?



Răspuns :

[tex]\frac{n}{9} =a+7=> n=9a+56\\\frac{n}{8} =b+5=>n=8b+40\\72:n=72:(9a+56)=\frac{8}{a} +\frac{9}{7} \\72:n=72:(8a+40)=\frac{8}{b} +\frac{9}{5}\\[/tex]

Deci resturile sunt :[tex]\frac{9}{7} \frac{9}{5}[/tex].