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[tex]1 \frac{5}{6} - \frac{8}{3} + \frac{102}{100} - \frac{1}{50} + (2 {}^{2} ) {}^{1011} \div (2 + 2 {}^{3} \div 4) {}^{1010} [/tex]
VA ROG SA MA AJUTATI SI SCRIETI SI REZOLVAREA COMPLETA​


Răspuns :

Răspuns:

(1·6+5)/6-8/3+(102/100)⁽²-1/50+2²ˣ¹⁰¹¹:(2+2³:2²)¹⁰¹⁰=

²⁵⁾11/6-⁵⁰⁾8/3+³⁾51/50-³⁾1/50+2²⁰²²:(2+2³⁻²)¹⁰¹⁰=

(275-400+153-3)/150+2²⁰²²:4¹⁰¹⁰=

25/150+2²⁰²²:(2²)¹⁰¹⁰=

1/6+2²⁰²²⁻²⁰²⁰=

1/6+2²=

1/6+⁶⁾4=

(1+24)/6=

25/6=4 intregi 1/6

Răspuns:

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