Răspuns:
a. 200 mol Cu(OH)₂ = 19,6 kg Cu(OH)₂
b. 200 mol H₂O = 3,6 kg H₂O
Explicație:
M(CuO) = A(Cu) + A(O) = 64 + 16 = 80 g/mol = 80 kg/kmol
n(CuO) = m(CuO) / M(CuO) = 16 kg / 80 kg/kmol = 0,2 kmol = 200 mol
Cu(OH)₂ → CuO + H₂O
1 mol Cu(OH)₂.....1 mol CuO.....1 mol H₂O
x mol Cu(OH)₂...200 mol CuO...y mol H₂O
x = 200 mol Cu(OH)₂
y = 200 mol H₂O
M(Cu(OH)₂) = A(Cu) + 2A(O) + 2A(H) = 64 + 2 × 16 + 2 × 1 = 98 g/mol
m(Cu(OH)₂) = 200 mol × 98 g/mol = 19600g = 19,6 kg
M(H₂O) = 2A(H) + A(O) = 2 × 1 + 16 = 18 g/mol
m(H₂O) = 200 mol × 18 g/mol = 3600g = 3,6 kg
-Mihai
