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efectuati b³+1000t³= 1-64x³= a²+125y³= 8-27b³= va rog ​

Răspuns :

[tex]\it b^3+1000t^3=b^3+(10t)^3=(b+10t)(b^2-10bt+100t^2)\\ \\ 1-64x^3=1-(4x)^3=(1-4x)(1+4x+16x^2)\\ \\ \\ 8-27b^3=2^3-(3b)^3=(2-3b)(4+6b+9b^2)[/tex]