Răspuns:
Explicație pas cu pas:
a) 3x⁵-5x³ = x³·(3x²-5)
b) 2y⁶+18y = 2y·(y⁴+9)
c) 4a⁸-3a⁵ = a⁵·(4a³-3)
d) x³-2x²-3x = x·(x²-2x-3) = x·(x²-3x+x-3) =
=x·[x·(x-3)+(x-3)] = x·(x-3)(x+1)
e)5y⁴+3y²-y = y·(5y³+3y-1)
f) 4a³+3a⁴-7a⁷ = a³·(4+3a-7a⁴)
g) x⁴-2x³-x² = x²·(x²-2x-1)
h) 7t⁵-5t⁷ = t⁵·(7-5t²)