Răspuns:
Explicație pas cu pas:
[tex]\left[\begin{array}{ccc}-1&-2&3\\1&0&-1\\2&-1&-1\end{array}\right][/tex] =(-1)*0*(-1)+(-2)*(-1)*2+3*1*(-1)-2*0*3-(-1)*(-1)*(-1)-(-1)*1*(-2)=0
[tex]\left[\begin{array}{ccc}-2&1&3\\3&-2&1\\1&3&-2\end{array}\right][/tex]=(-2)*(-2)*(-2)+1*1*1+3*3*3-1*(-2)*3-3*1*(-2)-(-2)*3*1=38
0<38 Adevarat
[tex]\left[\begin{array}{ccc}x&1&2\\2&1&1\\1&2&1\end{array}\right][/tex]=2014=>x*1*1+1*1*1+2*2*2-1*1*2-2*1*x-1*2*1=2014=>-x+5=2014=>-x=2014-5=>-x=2009=>x=-2009
